2m^2+15m=8

Solution for 2m^2+15m=8 equation:

2m^2+15m=8

We move all terms to the left:

2m^2+15m-(8)=0

a = 2; b = 15; c = -8;
Δ = b2-4ac
Δ = 152-4·2·(-8)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-17}{2*2}=\frac{-32}{4}
=-8
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+17}{2*2}=\frac{2}{4}
=1/2
$